get_lc_namespace() — langchain Function Reference

Architecture documentation for the get_lc_namespace() function in structured.py from the langchain codebase.

Function python PromptManagement ExampleSelection

Entity Profile

PromptManagement→ ExampleSelection→ get_lc_namespace() — langchain Function Reference

Dependency Diagram

graph TD
  3a844540_f005_7d51_4704_c6c16b57b29e["get_lc_namespace()"]
  14de95af_eb88_e7a8_1ab1_98d03dd541e0["StructuredPrompt"]
  3a844540_f005_7d51_4704_c6c16b57b29e -->|defined in| 14de95af_eb88_e7a8_1ab1_98d03dd541e0
  style 3a844540_f005_7d51_4704_c6c16b57b29e fill:#6366f1,stroke:#818cf8,color:#fff

Relationship Graph

Source Code

libs/core/langchain_core/prompts/structured.py lines 75–84

    def get_lc_namespace(cls) -> list[str]:
        """Get the namespace of the LangChain object.

        For example, if the class is `langchain.llms.openai.OpenAI`, then the namespace
        is `["langchain", "llms", "openai"]`

        Returns:
            The namespace of the LangChain object.
        """
        return cls.__module__.split(".")