test_tool_injected_tool_call_id() — langchain Function Reference
Architecture documentation for the test_tool_injected_tool_call_id() function in test_tools.py from the langchain codebase.
Entity Profile
Dependency Diagram
graph TD dee033fa_6ef1_b520_d977_5d5f47a10a3d["test_tool_injected_tool_call_id()"] 8e7836ae_e72c_f670_72a5_4ca6d46e3555["test_tools.py"] dee033fa_6ef1_b520_d977_5d5f47a10a3d -->|defined in| 8e7836ae_e72c_f670_72a5_4ca6d46e3555 b621c544_d6db_7e8d_7240_9ce08870d71a["foo()"] dee033fa_6ef1_b520_d977_5d5f47a10a3d -->|calls| b621c544_d6db_7e8d_7240_9ce08870d71a style dee033fa_6ef1_b520_d977_5d5f47a10a3d fill:#6366f1,stroke:#818cf8,color:#fff
Relationship Graph
Source Code
libs/core/tests/unit_tests/test_tools.py lines 2512–2546
def test_tool_injected_tool_call_id() -> None:
@tool
def foo(x: int, tool_call_id: Annotated[str, InjectedToolCallId]) -> ToolMessage:
"""Foo."""
return ToolMessage(str(x), tool_call_id=tool_call_id)
assert foo.invoke(
{
"type": "tool_call",
"args": {"x": 0},
"name": "foo",
"id": "bar",
}
) == ToolMessage("0", tool_call_id="bar")
with pytest.raises(
ValueError,
match="When tool includes an InjectedToolCallId argument, "
"tool must always be invoked with a full model ToolCall",
):
assert foo.invoke({"x": 0})
@tool
def foo2(x: int, tool_call_id: Annotated[str, InjectedToolCallId()]) -> ToolMessage:
"""Foo."""
return ToolMessage(str(x), tool_call_id=tool_call_id)
assert foo2.invoke(
{
"type": "tool_call",
"args": {"x": 0},
"name": "foo",
"id": "bar",
}
) == ToolMessage("0", tool_call_id="bar")
Domain
Subdomains
Defined In
Calls
Source
Frequently Asked Questions
What does test_tool_injected_tool_call_id() do?
test_tool_injected_tool_call_id() is a function in the langchain codebase, defined in libs/core/tests/unit_tests/test_tools.py.
Where is test_tool_injected_tool_call_id() defined?
test_tool_injected_tool_call_id() is defined in libs/core/tests/unit_tests/test_tools.py at line 2512.
What does test_tool_injected_tool_call_id() call?
test_tool_injected_tool_call_id() calls 1 function(s): foo.
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